A) 3. A bag contains chocolates: 3 Snickers, 5 Hershey Bars, 6 Kit-Kat Bars, 6 Milky Ways
Without replacing any of the chocolates back to the bag
a) What is the probability of selecting 2 Snickers?
b) What is the probability of selecting a Snickers and Hershey Bar in that order?
c) What is the probability of selecting a Milky Way and a Kit Kat bar in that order?

The probability of selecting 2 Snickers is 3/190. The probability of selecting a Snickers and Hershey Bar in that order is 3/76. The probability of selecting a Milky Way and a Kit Kat bar in that order is 18/190.

Number of Snickers = 3

Number of Hershey Bars = 5

Number of Kit-Kat Bars = 6

Number of Milky Ways = 6

Total number of chocolates = 20

a) What is the probability of selecting 2 Snickers?

= 3/20 × 2/19

= 3/190

The probability of selecting 2 Snickers is 3/190

b) What is the probability of selecting a Snickers and Hershey Bar in that order?

= 3/20 × 5/19

= 3/76

The answer is 3/76

c) What is the probability of selecting a Milky Way and a Kit Kat bar in that order

= 6/20 × 6/19

= 18/190

The probability is 18/190

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o= 4(i) +3

step-by-step explanation:

o is your output value and i is your input value. so, for example, if we stuck 7 in as our input, we would first multiply by 4 ( pemdas ), which equals 28. then we would add 3 to 28, for a total output of 31. this may not be a graph, but, it is a way to solve your formula..