A can do a piece of work in 3 days and B in 6 days andShyam in 12 days. In how many days will they finish it when both work at it.​

Ram's 1 day's work =  

6 1

​  

Shyam's 1 day's work =  

121

​

The part of work in 2 day's by both =2(  

6 1 +  12 1  )=2(  122+1  )=2×  12 3 =  2 1

​

Please mark brainliest.

Step-by-step explanation:

Step-by-step explanation:

= 1/3 + 1/6 + 1/12 (LCM 12)

= 4/12 + 2/6 + 1/12

= 6/12

= 1/2

Therefore 1/2 = 2 days

They will all work together and finish the job in 2 days

please click thanks and mark brainliest if you like :)

the axial of symmetry

step-by-step explanation:

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."