The length of a rectangle is 4 inches more than its width. The area of the rectangle is equal to 5 inches more than 2 times the perimeter. Find the length and width of the rectangle

Step-by-step explanation:

 L = 4 + w

A = 2P - 4

lw = 2(2l +2w) - 4

lw = 4(l + w) - 4

(w+4)w = 4 ( w+4+w) -4

(w +4)w = 4(2w + 4) - 4

w^2 + 4w = 8w + 16 - 4

w^2 + 4w = 8w + 12

w^2 - 4w - 12 = 0

( w      -       6 )( w  +       2  ) = 0

w - 6 = 0 > w = 6 > L=10  ---> P = 32  and A = 60

w + 2 = 0 ---> w = -2 <--- width cannot be negative; disqualified/rejected

good luck!

cutie~

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0