In the straight line of gradient 3 and passes through the point (0,2), i. Write down the intercept. ii. Write down the equation,​

Ans:

i) y-int (0 , 2) and x-int (-2/3 , 0)

ii) y = 3x + 2

Step-by-step explanation:

we know:

m = 3 & point (0,2)

i

y-int is (0,2) because where x is 0 it intersects the y-axis

ii

from this we can sub it into the point slope formula which is:

y - y1 = m (x - x1)          (y1 and x1 being the values from a point lying on the line)

y - 2 = 3 (x - 0)

y - 2 = 3x

y = 3x + 2     < this is the equation

if you also need to find the x-int then:

to find x-int make y = 0 and solve for x

y = 3x + 2                     3x = - 2

0 = 3x + 2                       x = -2/3

therefore x-int is (-2/3,0)

8

step-by-step explanation:

find the vertical and horizontal asymptotes of the function f x = 5 x − 1 . to find the vertical asymptote, equate the denominator to zero and solve for . since the degree of the polynomial in the numerator is less than that of the denominator, the horizontal asymptote is .

step-by-step explanation: