Which of the following equations is of a parabola with a vertex at (1, 2)? O y = (x - 1) 2 - 2
Oy= (x - 1)2 + 2
O y = (x + 1)2 - 2
O y = (x + 1)2 + 2

the second option: (x-1)squared +2

Explanation:

The x value of the vertex can be found in the parenthesis after the x. However, you have to do the opposite value of it. So, since the paranthesis has (x-1) then that means that the vertex's x-value has to be 1.

For the y-value of the vertex, that can be found after the paranthesis. This value will not be used as the opposite like with the x-value. So, we know that in (x-1)^2 +2 the "+2" indicates the y-value to be 2.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

4444444444444 i think