Looking for the equation, slope, and y-intercept of: (1,-3) and (0,-1)

Equation: y = -2x - 1

Slope: -2

Y intercept: -1

Step-by-step explanation:

First, find the slope using rise over run, (y2 - y1) / (x2 - x1):

(y2 - y1) / (x2 - x1)

(-1 + 3) / (0 - 1)

2 / -1

= -2

So, the slope is -2. Plug this and a point into slope intercept form, y = mx + b, and solve for b:

y = mx + b

-1 = -2(0) + b

-1 = 0 + b

-1 = b

So, the y intercept is -1. Create the equation by plugging in the slope and b into y = mx + b:

y = mx + b

y = -2x - 1

The equation of the line is y = -2x - 1.

y=-2x-1. Slope is -2 and y int. is -1.

Step-by-step explanation:

First, you need to find the slope by using the slope formula y2-y1/x2-x1. Plug in the x and y coordinates, which simplifies as -1-(-3)/0-1, and furthermore to 2/-1, or -2. The y intercept can be found by the second point, (0,-1). Therefore, the y int. is -1.

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step-by-step explanation:

answer

false

explanation

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