Mathematics, 02.08.2021 15:40, nathanphelps2468

Solve it please. Just wanted to check my drawing skill but please solve it

Answers: 3

Show answers

Answers

answered: swaggyd6603

Step-by-step explanation:

I'm assuming that strange looking thing is a 9, so begin by multiplying both sides by that denominator to get:

$x-9=\sqrt{x}+3$ then subtract 3 from both sides to get

$x-12=\sqrt{x}$ and then square both sides to get

x^2-24x+144=x and get everything on one side to solve for x by factoring:

x^2-25x+144=0 and factor that however it is you have learned to factor second-degree polynomials to get that

x = 16 and x = 9. We have to check for extraneous solutions because anytime you manipulate an equation, as we did by squaring both sides, you run the risk of these solutions that actually don't work when you plug them back into the original equation. Let's try 16 first:

$\frac{16-9}{\sqrt{16}+3 }=1$ If 16 is a solution, then this statement will be mathematically true.

$\frac{7}{4+3}=1$ and $\frac{7}{7}=1$ so 16 works. Let's try 9:

$\frac{9-9}{\sqrt{9}+3 }=1$ We know that one doesn't work, because 9-9 = 0 and 0 over anything = 0, not 1.

x = 16 is the only solution.

answered: skrrtgod408

x = 16

Step-by-step explanation:

$\frac{x-9}{\sqrt{x}+3}=1$

Cross multiply,

x - 9 = √x + 3

Subtract 3 from both sides

x - 9 - 3 = √x

x - 12 = √x

Square both sides

(x -12)² = (√x)²

x² - 2 * x*12 + 12² = x

x² - 24x + 144 = x

x² - 24x + 144 - x = 0

x² - 25x + 144 = 0

Sum = -25

Product = 144

Factors = -9 , -16 {(-9)+(-16) = -25 & (-)*(-16) = 144}

x² - 25x + 144 = 0

x² - 16x - 9x + (-9)*(-16) = 0

x(x - 16) - 9(x - 16) = 0

(x - 16) (x - 9) = 0

x - 16 = 0 ; x - 9 = 0

x = 16 ; x = 9

x = 9 is an extraneous solution.

When we plug in 9 in the LHS of the equation,

LHS = $\frac{9-9}{\sqrt{9}+3}$

$= \frac{0}{3+3}$

= 0 ≠ RHS

So, x = 16 is the only solution

answered: Guest

I’m tome

answered: Guest

c. x=2.4cm

step-by-step explanation:

similar triangles are triangles which have the same shape but not the same size. this means their angle measures are equal but their side lengths are not instead they are proportional. to solve, we will set up a proportion and solve.

a proportion is two equal ratios set equal to each other. we form the ratios by finding corresponding sides (sides which match to each other on both triangles by their position). out ratios will be one side of the small triangle over the corresponding side on the big triangle as shown below:

$\frac{little}{big} =\frac{side mn}{side ab}=\frac{side on}{side cb}$ .