A simple random sample of 49 8th graders at a large suburban middle school indicated that 88% of them are involved with some type of after school activity. Find the margin of error associated with a 90% confidence interval that estimates the proportion of them that are involved in an after school activity.

The margin of error associated with a 90% confidence interval that estimates the proportion of them that are involved in an after school activity is 0.0764.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the z-score that has a p-value of .

The margin of error is:

90% confidence level

So , z is the value of Z that has a p-value of , so .

A simple random sample of 49 8th graders at a large suburban middle school indicated that 88% of them are involved with some type of after school activity.

This means that

Margin of error:

The margin of error associated with a 90% confidence interval that estimates the proportion of them that are involved in an after school activity is 0.0764.

could you give more information?

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.