An object is launched at 14.7 meters per second from an 88.2 meter tall platform. The equation for the object's height (ℎ)
(
h
)
at time
()
(
t
)
seconds after launch is
ℎ()=−4.92+14.7+88.2
h
(
t
)
=
−
4.9
t
2
+
14.7
t
+
88.2
. Assuming
=0
t
=
0
is when the object is launched and
ℎ=0
h
=
0
is when the object is level with the ground, when does the object strike the ground?

Pls! does anybody know a shortcut for answering these types of questions in the future?

Complete the solution of the equation. find the value of y when x equals -5. -4x - 8y = -52

Someone answer asap for ! a ball is rolled down a ramp. the height, f(x), in meters, of the ball x seconds after it is released is modeled by the function f(x) = x²- 10x + 25 for all values of x from 0 to 5. which statement about the ball is true? a. the maximum height of the ball is 5 meters b. the height of the ball increases from 0 to 5 meters above the ground. c. the ball has traveled 5 meters when it reaches the bottom of the ramp. d. the ball has been traveling for 5 seconds when it reaches the bottom of the ramp