The two dot plots below show the heights of some sixth graders and some seventh graders: The mean absolute deviation (MAD) for the first set of data is 1.2 and the MAD for the second set of data is 1.7. Approximately how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders

The number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4

Step-by-step explanation:

From the question, the mean absolute deviation (MAD) of the sixth graders = 1.2 and that of the seventh graders = 1.7

The variability in the heights of the sixth graders = 1.2

The variability in the heights of the seventh graders = 1.7

To calculate how many times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders, we will divide the variability of the seventh graders by the variability of the sixth graders

That is, 1.7/ 1.2 = 1.4167 ≅ 1.4

Hence, the number of times the variability in the heights of the sixth graders is the variability in the heights of the seventh graders is approximately 1.4

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).