If f(×)=16×-30 and g(×)=14×-6, for which value of x does (f-g)(x)=0

Step-by-step explanation:

 are the equations that you've given us.

Now if we plot these two equations on the graph we notice there's an intersection at (12,162). Therefore meaning that .

We can prove that by doing the following calculations to prove that both sides are equal to each other.

The left side of the equal sign:

Step 1: Write the equation down:

Step 2: Substitute x for the numerical value we found.

Step 3: We will multiply first, giving us 192.

Step 4: Subtract 192 from 30. Which gives us 162.

The right side of the equal sign:

Step 1: Write the equation down:

Step 2: Substitute x for the numerical value we found.

Step 3: We will multiply first, giving us 168.

Step 4: Subtract 168 from 6. Which gives us 162.

We know that because when substituting x with 12, we get 162 on both sides. Therefore making this statement true and valid.

see explanation

step-by-step explanation:

since the sequence is geometric there is a common ratio r between consecutive terms, that is

r = 4 ÷ - 2 = - 2

r = - 8 ÷ 4 = - 2

r = 16 ÷ 8 = - 2

the next term - 13 must be incorrect as it should be - 32 for the sequence to be geometric.

the first 4 terms are therefore geometric with common ratio r = - 2

need points to ask question

step-by-step explanation: