I need help with this question !

3x -2 ≤ 2x +1

3x ≤ 2x +3

x ≤ 3

so its {x|x∈ℝ, x ≤ 3}

x ≤ 3

Step-by-step explanation:

3x-2 ≤ 2x+1

Subtract 2x from each side

3x-2x-2 ≤ 2x-2x+1

x-2 ≤ 1

Add 2 to each side

x-2+2 ≤ 1+2

x ≤ 3

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

d no solution

step-by-step explanation: