The function below is differentiable at (0, 0). Give an equation of the plane tangents to the graph of f at the origin

Given: m∠ adb = m∠cdb ad ≅ dc prove: m∠ bac = m∠bca lol

In right ∆abc shown below, the midpoint of hypotenuse ac is located at d and segment bd is drawn. if ab = 12 and bc = 16, then explain why bd = 10. hint: consider what you know about the diagonals of a rectangle.

What are the values of a, b, and c in the quadratic equation 0 = x2 – 3x - 2? a = 1, b = 3, c = 2 a=, b = -3,c=-2 a = 1, b = 3, c= 2 a = 1.0= -3, c = 2