Mark rolls a fair dice 36 times. How many times would Mark expect to roll a number greater than 5?​

Let X be the number of times a Dice rolls 4.

Expected value is 96/6 = 16.

Step-by-step explanation:

6

Step-by-step explanation:

In a dice, there are 6 faces, there's {1, 2, 3, 4, 5, 6}.

So when the question asks a number greater than 5 it means that it wants the "6". The probability to get the "6" is 1/6. So to find the expected value you just times the number of rolls with the probability which means 36 × 1/6 which equals to 6 times

8y^50

step-by-step explanation: