Find octal expansion of (B5D)16.

b5d₁₆ = 11×16² + 5×16¹ + 13×16⁰

… = 11×(2×8)² + 5×(2×8)¹ + 13×(2×8)⁰

… = 11×4×8² + 5×2×8¹ + 13×8⁰

… = 44×8² + 10×8¹ + 13×8⁰

… = (40 + 4)×8² + (8 + 2)×8¹ + (8 + 5)×8⁰

… = (5×8 + 4)×8² + (1×8 + 2)×8¹ + (1×8 + 5)×8⁰

… = 5×8³ + 4×8² + 1×8² + 2×8¹ + 1×8¹ + 5×8⁰

… = 5×8³ + 5×8² + 3×8¹ + 5×8⁰

… = 5535₈

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.

24/56=hx^7

step-by-step explanation: