Ông A có 1 thửa ruộng hình tứ giác có độ dài các cạnh và 1 đường chéo lần lượt là: 5m, 6m, 8m, 7m, 9m. Ông a muốn trồng hoa trên toàn bộ thửa ruộng với chi phí mua hoa là 101000 đồng/1m^2. Tính tổng chi phí mua hoa?

option a, c,d are correct.

step-by-step explanation:

from the given figure, it is given that z is equidistant from the sides of the triangle rst, then from triangle tzb and triangle szb, we have

tz=sz(given)

bz=zb(common)

therefore, by rhs rule,δtzb ≅δszb

by cpctc, sz≅tz

also, from δctz and δasz,

tz=sz(given)

∠tcz=∠saz(90°)

by rhs rule, δctz ≅ δasz, therefore by cpctc, ∠ctz≅∠asz

also,from δasz and δzsb,

zs=sz(common)

∠zbs=∠saz=90°

by rhs rule, δasz ≅δzsb, therefore, by cpctc, ∠asz≅∠zsb

hence, option a, c,d are correct.

its 60

4 x 12 = 48

3 x 4 = 12

48 + 12 = 60

yeeeet

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step-by-step explanation:

∈3,600

step-by-step explanation: