Samuel was given the diagram below and asked to prove that AC = BD. What would be the fifth step of the proof?
Given: Quadrilateral ABCD is a rectangle.
Prove: AC BD
Statements
1. Quadrilateral ABCD is a rectangle
2. AB a CD
3. ZBAD ZODA
4. ADE AD
5.
6. AC 230
Reasons
Given
Opposite sides of a rectangle are equa.
All angles of a rectande are equal.
Reflexive Property of Equality
Corresponding parts of congruent
triangles are congruent
с
A. AABD = SACD, using the SSS congruence theorem
B. ABAD = ACDA, using the SAS congruence theorem
C. 4ACB ACDA, using the SAS congruence theorem
D. ABC = ADAC, using the AAA congruence theorem
PREVIOUS

it should be a and d. lmk if i'm wrong xd

the final price would be 29.6925

step-by-step explanation:

39.59 minus 25% equals 29.6925

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: