Greg drove at a constant speed in a rainstorm for 282 miles. He took a break, and the rain stopped He then drove 250 mies at a spoed that was 3 miles per hour faster than his previous speed. If he drove for 11 hours, find the car's speed for each part of the trip
The rate of the car in the rain was mph.

9514 1404 393

Step-by-step explanation:

The speed during the first part of the trip can be represented by x. Then the speed during the second part is x+3 and the total time is ...

  time = distance/speed

  11 = 282/x +250/(x+3)

  11(x)(x+3) = 282(x +3) +250(x) . . . . multiply by x(x+3)

  11x^2 -499x -846 = 0 . . . . . . . put in standard form

  (11x +18)(x -47) = 0 . . . . . . . factor

  x = 47 . . . . . positive solution (makes x-47=0)

The rate of the car in the rain was 47 mph. The rate of the car after the break was 50 mph.

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b