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Mathematics, 21.06.2019 15:10, pampam49
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Mathematics, 21.06.2019 21:00, gujacksongu6
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Given: ae ≅ ce ; de ≅ be prove: abcd is a parallelogram. we have that ab || dc. by a similar argument used to prove that △aeb ≅ △ced, we can show that △ ≅ △ceb by. so, ∠cad ≅ ∠ by cpctc. therefore, ad || bc by the converse of the theorem. since both pair of opposite sides are parallel, quadrilateral abcd is a parallelogram.
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Cos(x)^3-cos(2*x)+cos(x) = 0...
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Mathematics, 22.06.2021 16:30
