Select the correct answer from the drop-down menu. Z1 = 4cis (pi/2) and Z2=3cis(3pi/2)
The product of Z1 and Z2 is

z₁ × z₂ = 12·cis(2·π)

Step-by-step explanation:

z₁ = 4·cis(π/2), z₂ = 3·cis(3·π/2)

We have;

z₁ = 4·cis(π/2) = 4·(cos(π/2) + i·sin(π/2))

z₂ = 3·cis(3·π/2) = 3·(cos(3·π/2) + i·sin(3·π/2))

According to De Moivre's Theorem,

z₁ × z₂ = 4×3×(cos(π/2 + 3·π/2) + i·sin(π/2 + 3·π/2)) = 12·(cos(2·π) + i·sin(2·π))

∴ z₁ × z₂ = 12·cis(2·π)

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

step-by-step explanation:

hans did not square the 40-unit side; he merely multiplied it by 2.   incorrect.