In how many ways can 10 people be divided into three groups with 2, 3, and 5 people respectively?

2100

Step-by-step explanation:

In how many ways can a group of 10 people be divided into three groups consisting of 2,3, and 5 people?

First, you need to choose 4 people to fill the first group.

The number of ways is (104) which equals to 210.

Then, pick 3 more people out of the remaining 6 to be in the second group. And then, pick 3 more out of the remaining 3.

However, we need to divide it by 2, since we don’t really care on the order of selection of group.

(63)(33)/2=10

So, there are 210 x 10 = 2100 ways

hmmm I read JeremyBrooks answer... I think that it might be different...

i think it is 2520

of the 10 you first choose 2

10 choose 2 = 45 ways

in each of the 45 "chooses" you now

pick a group of 3 of the 8 left

8 choose 3 = that is 56

of the five people left you choose 5

5 choose 5 = 1

so the possibilities are 45*56 * 1 = 2520

Step-by-step explanation:

answer: 1) twenty-seven times y

              2) twenty-seven multiplied by y

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!