How much is 3p-4p+r less than 4p+3q-5r​

3p−4q+r) is (p + 7q - 6r)(p+7q−6r) less than (4p+3q-5r)(4p+3q−5r) .

Let (3p-4q+r)(3p−4q+r) is 'x' less than (4p+3q-5r)(4p+3q−5r) . Then

3p-4q+r = 4p+3q-5r - x→3p−4q+r=4p+3q−5r−x

x= 4p+3q-5r - (3p-4q+r)→x=4p+3q−5r−(3p−4q+r)

x= 4p+3q-5r - 3p + 4q - r→x=4p+3q−5r−3p+4q−r

x= 4p- 3p +3q +4q - 5r - r→x=4p−3p+3q+4q−5r−r

x= p + 7q - 6r→x=p+7q−6r

Thus (3p-4q+r)(3p−4q+r) is (p + 7q - 6r)(p+7q−6r) less than (4p+3q-5r)(4p+3q−5r) .

5p+3q-6r

Step-by-step explanation:

4p+3q-5r -(3p-4p+r) = 4p+3q-5r-3p+4p-r = 5p+3q-6r

if u made a typo and the question is "How much is 3p-4q+r less than 4p+3q-5r", the answer is p+7q-6r​

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step-by-step explanation: