On a coordinate plane, a curved line with a minimum value of (negative 2.5, negative 12) and a maximum value of (0, negative 3) crosses the x-axis at (negative 4, 0) and crosses the y-axis at (0, negative 3). Which statement is true about the graphed function?

F(x) < 0 over the interval (–∞, –4)
F(x) < 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –3)
F(x) > 0 over the interval (–∞, –4)

f(x) > 0 over the interval  (–∞, –4)

Step-by-step explanation:

We know that:

Our curve has a minimum at (-2.5, -12)

Our curve has a maximum at (0, - 3)  (I assume that is a local maximum).

We know that the curve crosses the x-axes at (-4, 0)

We know that the curve crosses the y-axis at (0, -3)

Notice that when our curve crosses the x-axis at (-4, 0), it goes from above the axis to below the axis.

How we know this?

Remember that "crossing" the x-axis means that the sign of f(x) changes.

At the value x = -2.5  (which is larger than x = -4) the function is negative.

f(-2.5) = -12

and:

f(-4) = 0

So we can see that after f(x) crosses the x-axis at x = -4, the function is negative.

This means that before that point, the function must be positive.

So for values of x smaller than -4, the function should be larger than zero.

f(x) > 0 if x < -4

From this, we can conclude that in the range (-∞, –4), the function is above the x-axis.

Then we would write this as:

f(x) > 0 over the interval  (–∞, –4)

The correct option is the last option.

good job you smart son of a gun you are smarter that einstein. 7

answer: 1+1

step-by-step explanation: 1+1 is at least 2