One positive integer is 3 less than twice another. th sum of their squares is 306. find the integers ​

let's call the first integer x, and the second y.

just to be able to talk about them.

one positive integer is 3 less than twice another

x = 2y -3

x² + y ² = 306

integers means whole numbers, and they must be positive.

x² + y ² = 306

can be rewritten as

x² = 306 -y²

x = sqrt(306 -y²)

sqrt means square root, obviously.

let's plug this last expression into

x² + y ² = 306

(sqrt(306 -y²))² = 2y -3

in this case, the square root and the (...)² cancel each other. so...

306 -y² = 2y -3

rewrite

309 -y² = 2y

309 = y² +2y

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screw all this. I just tried it out with numbers in desmos (see screenshot), because I got stuck

the numbers are 9 and 15. it was honestly just easier to try inputs out than to solve this system.

sorry I can't give you insight here. but just doing it anyways might be the key massage.

c

step-by-step explanation:

i think because what else can be a sample of every member

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: