Describe the domain of this function d=4300x/x^2 +40

f(x) = x^3 -2x^2 -3x

x( x^2 -2x-3)

x( x^2 +x -3x -3)

x( x(x+1) -3(x+1))

x( x-3)( x+1)

so zeroes are 0, 3,-1

its (2) option

answer: the answer is b. i think hope i got it correct

step-by-step explanation:

for future students the answer is b

hope i

-lavira: )