I operate a small convenience store. Typically, from 10 am to 11 am, I get 23 customers. What is the standard deviation of the number of customers that might check out between 10.15 am and 10.30 am

The standard deviation of the number of customers that might check out between 10.15 am and 10.30 am is 2.4.

Step-by-step explanation:

We have the mean during a time interval, so the Poisson distribution is used.

Poisson distribution:

In the Poisson distribution, the standard deviation is the square root of the mean.

Typically, from 10 am to 11 am, I get 23 customers.

In an hour, you get 23 customers.

What is the standard deviation of the number of customers that might check out between 10.15 am and 10.30 am?

In this period, there are 15 minutes, that is, one fourth of an hour, so:

And the standard deviation will be the square root of the mean, so:

The standard deviation of the number of customers that might check out between 10.15 am and 10.30 am is 2.4.

hello, sorry being so rude after all that fighting i found it kind of funny, so as me saying sorry here is an answer!

since the table showed her that   2km = 2000m.

to determine, how many km in 2000m, she would divide by 1000.

= 2000 / 1000 = 2 km.

similarly, for 8000m = 8000 / 1000 = 8 km

cheers to savings

~

your pal papaguy