Mathematics, 23.07.2021 01:10, Gearyjames8
Suppose that $17,965 is invested at an interest rate of 6.6 % per year, compounded continuously. a) Find the exponential function that describes the amount in the account after time t, in years. b) What is the balance after 1 year? 2 years? 5 years? 10 years? c) What is the doubling time? a) The exponential growth function is P(t) nothing. (Type exponential notation with positive exponents. Do not simplify. Use integers or decimals for any numbers in the equation.) b) The balance after 1 year is $ nothing. (Simplify your answers. Round to two decimal places as needed.) The balance after 2 years is $ nothing. (Simplify your answers. Round to two decimal places as needed.) The balance after 5 years is $ nothing. (Simplify your answers. Round to two decimal places as needed.) The balance after 10 years is $ nothing. (Simplify your answers. Round to two decimal places as needed.) c) The doubling time is nothing years. (Simplify your answers. Round to one decimal place as needed.)
Answers: 2
Mathematics, 21.06.2019 17:50, amcdonald009
To solve the system of equations below, grace isolated the variable y in the first equation and then substituted into the second equation. what was the resulting equation? 3y=12x x^2/4+y^2/9=1
Answers: 1
Mathematics, 21.06.2019 19:00, Islandgirl67
What are the solutions of the system? solve by graphing. y = x^2 + 3x + 2 y = 2x + 2
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Mathematics, 21.06.2019 20:20, jackiediaz
One of every 20 customers reports poor customer service on your company’s customer satisfaction survey. you have just created a new process that should cut the number of poor customer service complaints in half. what percentage of customers would you expect to report poor service after this process is implemented? 1.) 5% 2.) 10% 3.) 2% 4.) 2.5%
Answers: 1
Mathematics, 21.06.2019 20:40, genyjoannerubiera
Sh what is the value of x? ox= 2.25 x = 11.25 ox= x = 22 1 (2x + 10) seo - (6x + 1) -- nie
Answers: 3
Suppose that $17,965 is invested at an interest rate of 6.6 % per year, compounded continuously....
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