What are the zeros of f(x) = x2 - 8x+16? O A. x= 4 only
B. x = -4 and x = 4
C. X=-2 and x = 8
D. x=-4 only

x=4

Step-by-step explanation:

f(x) = x^2 - 8x+16

Set equal to zero

0 = x^2 -8x +16

Factor

what 2 numbers multiply to 16 and add to -8

-4*-4 = 16

-4+-4 = -8

0= (x-4)(x-4)

Using the zero product property

x-4 = 0  x-4 =0

x=4  x=4

table 3 represents a direct variation function. : )