Plato Help! For the Midwest region, the average number of sales orders per representative for the group that had training is
(0.46, 0.38, 0.54, 0.76) more than the average number of sales per representative for the group that had no training.

For the Northeast region, the average number of sales orders per representative for the group that had training is
(0.56, 0.44, 1.48, 0.74) more than the average number of sales per representative for the group that had no training.

The data from the sales director’s study indicates that the one-month training program (does not increase, increases)
sales

1. Difference in midwest = 0.38

Does not increase

2. Difference in northeast = 0.74

Increase

MIssing information;

                        3 month sales order

                          Training                 No training

Midwest                 234                           196

Northeast               252                           178

Total number of sales representative = 200

Find:

Difference

Computation:

Assume;

1. Number of sales representative in midwest = 200 / 2 = 100

Number of sales representative in northeast = 200 / 2 = 100

Difference in midwest = [Training - No training] / Number of sales representative in midwest

Difference in midwest = [234 - 196] / 100

Difference in midwest = 0.38

Does not increase

2. Difference in northeast = [Training - No training] / Number of sales representative in northeast

Difference in northeast = [252 - 178] / 100

Difference in northeast = 0.74

Increase

Learn more:

b

step-by-step explanation:

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}