Dp
dt = t
2p − p + t
2 − 1.

dp/dt = t ² p - p + t ² - 1

Factorize the right side:

dp/dt = p (t ² - 1) + (t ² - 1)

dp/dt = (p + 1) (t ² - 1)

So the differential equation is separable as

dp/(p + 1) = (t ² - 1) dt

Integrate both sides:

∫ dp/(p + 1) = ∫ (t ² - 1) dt

ln|p + 1| = t ³/3 - t + C

Solve for p :

p + 1 = exp(t ³/3 - t + C )

p + 1 = C exp(t ³/3 - t )

p = C exp(t ³/3 - t ) - 1

answ9x x 3=

step-by-step explanation:

dude thats to long figure it

step-by-step explanation: