Determine the x- and y- intercepts for the graph defined by the given equation. y = 7x + 3 a. x-intercept is ( 3, 0) y-intercept is (0, negative StartFraction 3 Over 7 EndFraction) c. x-intercept is (0, negative StartFraction 3 Over 7 EndFraction) y-intercept is ( 3, 0) b. x-intercept is (negative StartFraction 3 Over 7 EndFraction, 0) y-intercept is (0, 3) d. x-intercept is (3, 0) y-intercept is (negative StartFraction 3 Over 7 EndFraction, 0)

x-intercept is (-3/7, 0) and the y-intercept is at (0, 3)

Step-by-step explanation:

Given the function y = 7x + 3

The x-intercept occurs at y = 0. Substituting y = 0 into the expression, we will have:

0 = 7x + 3

7x + 3 = 0

7x = -3

x = -3/7

Similarly, the y-intercept occurs at x = 0. Substituting x = 0 into the expression, we will have:

y = 7(0) + 3

y = 0 + 3

y = 3

Hence the x-intercept is (-3/7, 0) and the y-intercept is at (0, 3)

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)