How many terms are in the following geometric sequence? Type your numerical answer only. Do not type any additional characters. 0.0625, 0,25, 1, 4194304

Given:

The given geometric sequence is:

0.0625, 0.25, 1, ..., 4194304

To find:

The number of terms in the given geometric sequence.

Solution:

We have,

0.0625, 0.25, 1, ..., 4194304

Here, the first term is 0.0625 and the common ratio is:

The nth term of a geometric sequence is:

Where, a is the first term and r is the common ratio.

Putting in the above formula, we get

On comparing both sides, we get

Therefore, the number of terms in the given geometric sequence is 14.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11