Determine which lines are parallel and which are not parallel. Explain your reasoning. 1. m∠3=69°, m∠7=71°

2. m∠3=76°, m∠8=114°

(please explain!!)

If M and N are parallel, then the correspondent angles generated by the intersection with line R (or line S) should be equal.

So, if M and N are parallel, we should get that angles 2 and angle 4 are equal, as both of these are on the fourth quadrant of the intersection with the same line.

Similarly, if R and S are parallel, then correspondent angles generated by the intersection with line M (or line N) should be equal, this means that:

angle 3 and angle 7 should be equal.

Also remember that if we have two lines intersecting, generating 4 angles, any pair of two adjacent angles will always add to 180°.

Here we have two cases:

1)  m∠3=69°, m∠7=71°

Here we can see that:

m∠3 ≠ m∠7

Thus, lines  R and S are not parallel.

And here we do not have any information on the angles 1, 2, 5, and 6, so we can't compare the angles generated by line N with the ones generated by line M, so we can not know if lines N and M are parallel or not.

2) Now we have that:

m∠3=76°  , m∠8=114°

Notice that angle 8 and angle 7 are adjacent, then we have that:

∠7 + ∠8 = 180°

And we know that:

∠8 = 114°

Then:

∠7 + 114° = 180°

∠7 = 180° - 114° = 76°

Then we have:

∠7 = ∠3

From this we can conclude that lines R and S are parallel.

(again, we can not do anything with lines N and M)

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3