Show that (x+1)(x+3)(x+5) can be written in the form ax3+bx2+cx+d where a b c and d are all positive intergers

Step-by-step explanation:

(x+1)(x+3)(x+5), multiply first two parenthesis

(x² +3x +x +3)(x+5), combine like terms

(x² +4x +3) (x+5), multiply the parenthesis

(x³ +5x² +4x² +20x +3x +15), combine like terms

x³ +9x² +23x +15 is in the form ax³ +bx² +cx +d

a=1, b=9, c=23, d=15 are all positive integers

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)