What is the solution to 3×^2-2×+4=0

this has no real solution.

only in the realm of complex and imaginary numbers.

x = 1/3 ± sqrt(11)i/3

Step-by-step explanation:

I read as the equation to be solved :

3x² - 2x + 4 = 0

the solution to such a quadratic equation is

x =(-b ± sqrt(b² - 4ac))/(2a)

in our case

a=3

b=-2

c=4

so,

x = (2 ± sqrt(4 - 48))/6 = (2 ± sqrt(-44))/6 =

= (2 ± sqrt(4×-11))/6 = (2 ± 2×sqrt(-11))/6 =

= (1 ± sqrt(11)×i)/3 = 1/3 ± sqrt(11)i/3

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.