A committee of 3 is to be selected randomly from a group of 3 men and 2 women. Let X represent the number of women on the committee. Find the probability
distribution of X.

Total number of ways to select 3 people from the 5 total: 5!/(3! (5 - 3)!) = 10

• Number of ways of picking 0 women:

• Number of ways of picking 1 woman:

• Number of ways of picking 2 women:

• Number of ways of picking 3 women: 0, since there are only 2 to choose from

Then X has the probability mass function

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