Solve log6 + log6 (x-1) = 1

Step-by-step explanation:

We are here given a logarithmic equation and we need to solve it out and then find the value of x. The given equation is ,

Here I am assuming that the base of the logarithm is 6 . The equation can be written as ,

Recall the property of log as , , on using this property we have ,

Simplify ,

We know that , if then in expotential form it can be expressed as . Using this we have ,

Simplify ,

Add 1 both sides ,

Therefore ,

Hence the value of x is 7 .

7! = 7×6×5×4×3×2

3! = 3× 2

as 7! is multiple of 3! because 7! contains 3! that is 3× 2 as factor

so 7! /(3! ) = 7× 6× 5× 4

= 42 × 20

= 840

its b) 840✌✌✌

dhruv⭐