Assume that a procedure yields a binomial distribution with a trial repeated n times. Use the binomial probability formula to find the probability of x successes given the probability p of success on a single trial. n= 64, x= 3, p= 0.04

0.2210

Step-by-step explanation:

If p = 0.04

then 1-p = 1 - 0.04 = 0.96

So we have the probability distribution value

as;

n C r * p^r * (1-p)^(n-r)

Thus;

64 C 3 * p^3 * (1-p)^(64-3)

= 64 C3 * 0.04^3 * 0.96^61

where 64 C 3 is 64 combination 3

= 41,664 * 0.04^3 * 0.96^61

= 0.2210

-9

step-by-step explanation:

false

step-by-step explanation:

the reason i say this is because for a certain length of sides you can pick any two and the length is wither equal or greater than the third side and in this case it's not.

3 + 5 = 8

8 is smaller than 9 which is the third side.

hope this : )