Lavro operates a popular hotdog stand. He sells 320 sausages per day at a price of $5.50 each. The previous year's sales show that for every $0.50 decrease in price, he
will sell another 40 sausages.
The equation that models this problem is:
R(x) = (price)
(number sold)
R(x) = (5.50 - 0.50x)(320 + 40x)
Question 3 (1 point)
What is his maximize potential revenue?

Given:

Lavro sells 320 sausages per day at a price of $5.50 each.

The previous year's sales show that for every $0.50 decrease in price, he  will sell another 40 sausages.

The equation that models this problem is:

To find:

The maximum potential revenue.

Solution:

We have,

It can be written as:

Differentiate with respect to x.

For critical points, .

Differentiate R'(x) with respect to x.

Since R''(x)<0, therefore function R(x) is maximum at . The maximum value is:

Therefore, the maximize potential revenue is $1805 at .

answer: the answer is one of

step-by-step explanation:   we are given to write a proper fraction where the whole is divided into an even number of equal parts less than ten, and an odd number of those parts exist.

an even number less than 10 may be one of 2, 4, 6 or 8. so, the whole may be one of these four evens.

now, an odd number of these parts must exist, so the numerator must be an odd number, one of 1, 3, 5 or 7. it cannot be 9 because then the fraction will become improper.

thus, our fraction may be one of the following

step-by-step explanation:

their are no angles. sorry cant .