13 A traffic roundabout has a circular garden in the centre and two lanes for traffic
encircling the garden. The diameter of the
garden is 16 metres and each lane is 3 metres
wide. Each lane is to be resurfaced. Calculate
the area to be resurfaced. Answer in square
metres to the nearest whole number.

Step-by-step explanation:

The area to be resurfaced is the area of the

whole circle including garden and lanes minus  

the area of the garden.

Area of a circle is (pi)r2

radius of garden is (1/2)diameter = 8 m

Garden area:  (pi)82 = 64(pi) m2

Diameter of garden plus traffic lanes is

16 + 2(6) because we add 6 m to both sides

of the diameter of the garden.

Full diameter = 16+12 = 28 m

Full radius = 28/2 = 14 m

Full area:  (pi)142 = 196(pi) m2

Area to be resurfaced:

196(pi) - 64(pi) = 132(pi) m2  ≅ 415 m2

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)