Solving quadratic equations is one of the main topics of this unit. Some quadratic equations can be solved with only one method, some can be solved with
multiple methods, and some can't be solved at all. Think about a task in your
daily life that can be accomplished in a variety of ways. How do you decide the
best course of action for accomplishing that task? How is this process like
choosing a method for solving a quadratic equation that can be solved in
multiple ways?

I need help I’m not sure what to put as my response??

the answer is. -82562234434584

step-by-step explanation:

i believe it is c.y = 9x

rise over run. 9 units up over 1 unit right or 9/1

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.