Two numbers are in the ratio 2:3 and their sum id 45 then find both number​

Step-by-step explanation:

Let the two numbers be 2x and 3x.

According to the question,

2x+3x=45

5x=45

x=45/5

x=9

so th required numbers are 18 and 27 as

2x=2*9=18

3x=3*9=27

It is given that,

→ Two numbers are in the ratio 2:3.

→ Their sum is 45.

We have to,

find the both required numbers.

Now assume numbers as,

→ 2y and 3y

As per the given information,

→ 2y + 3y = 45

First we can find the value of y,

→ 2y + 3y = 45

→ 5y = 45

→ y = 45/5

→ [y = 9]

The given ratio is,

→ 2 : 3

Let's find the value of 2y,

→ 2y --- {y = 9}

→ 2 × (9)

→ 18

Let's find the value of 3y,

→ 3y --- {y = 9}

→ 3 × (9)

→ 27

Hence, the number is 18 and 27.

1 number

if we use a graphing calculator, there is only one such number that satisfies the conclusion of the mean value theorem, that is, a number such that

where the right-hand side is the average rate of change of f on the interval [0.5,0.75], which is the slope of the secant line.

in the attached graph, the black line is the secant line which has its slope as the average rate of change of f on [0.5,0.75], while the orange line is the only tangent line to the graph of f in the interval that satisfies the mvt conclusion.