Complete the missing parts of the
table for the following function.
y=(1/5)^x

X-2 -1 0 1 2 3

y [?] [ ] 1 1/5. 1/?
1/125

see below

Step-by-step explanation:

we are given a exponential function

we want to figure out the missing values of y for x i.e (-2,-1, and 2) to do we can consider substituting so,

when x is -2 y should be

rewrite ⅕ in exponent notation:

by law of exponent we obtain:

simplify square:

when x is -1:

rewrite ⅕ in exponent notation:

use law of exponent which yields:

when x is 3:

by law of exponent we obtain:

simplify square which yields:

< 4, -5>

step-by-step explanation:

starting from g. we move 4 right and then 5 down to get to h. that means the vector is < 4, -5>

75

step-by-step explanation: