Help pls! Suppose ten distinct, positive integers have a median of 10. ("Distinct integers" means that no two integers are the same.)

What is the smallest the average of those ten integers could be?

Explain your answer in complete sentences.

8.4

Step-by-step explanation:

Since we want to minimize the average, the integers should be made as small as possible. So, we have 4 integers:

1, 2, 3, 4

However, the median must be 10. The next two integers must have an average of 10 - and since the integers are distinct, we should use:

9, 11

From there, we use the smallest integers (that are still above 11) possible:

12, 13, 14, 15

The average of these 10 integers is 84/10, or 8.4.

The median is still 10, because (9+11)/2 is 10.

the answer

b. they are parallel and will never intersect.