I need help solving this: Complete the coordinate proof of the theorem.

Given: ABCD is a parallelogram.

Prove: The diagonals of ​ABCD​ bisect each other.

Parallelogram in quadrant 1 of the coordinate plane with vertices at A begin ordered pair 0 comma 0 end ordered pair, B begin ordered pair a comma 0 end ordered pair, C begin ordered pair a plus c comma b end ordered pair and D.

Enter your answers in the boxes.

The coordinates of parallelogram ABCD are A(0, 0), B(a, 0), C(a+c, b), and D(_,_).

The coordinates of the midpoint of AC¯¯¯¯¯ are ( ​a+c2​,_).

The coordinates of the midpoint of BD¯¯¯¯¯ are (___,​ b2​).

The midpoints of the diagonals have the same coordinates.

Therefore, the diagonals of ​ABCD​ bisect each other.

true

explanation:

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the slope of the line is 60

one point on the line is (40,10)

step-by-step explanation:

in the equation outside the parenthesis the equation always tells you the slope. in this case it is 60.

in the parenthesis is also says 40 which is x because it is near the x and 10 is y because it is near y.

the answer is 99.