Consider the experiment of tossing a fair coin 3 times. For each coin, the possible outcomes are heads or tails.(a) List the equally likely events of the sample space for the three tosses.(b) What is the probability that all three coins come up heads? Notice that the complement of the event "3 heads" is "at least one tail." Use this information to compute the probability that there will be at least one tail.

a)

H - H - H

H - H - T

H - T - H

H - T - T

T - H - H

T - H - T

T - T - H

T - T - T

b)

0.125 = 12.5% probability that all three coins come up heads.

0.875 = 87.5% probability that there will be at least one tail.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Question a:

Considering H for heads, T for tails:

H - H - H

H - H - T

H - T - H

H - T - T

T - H - H

T - H - T

T - T - H

T - T - T

(b) What is the probability that all three coins come up heads?

One outcome(H - H - H) out of 8, so:

0.125 = 12.5% probability that all three coins come up heads.

Notice that the complement of the event "3 heads" is "at least one tail." Use this information to compute the probability that there will be at least one tail.

Sum of these probabilities is 100%, so:

1 - 0.125 = 0.875

0.875 = 87.5% probability that there will be at least one tail.

associative property hopes this ! : )

step-by-step explanation:

step-by-step explanation:

we can use this expression to calculate the energy gain as a particle moves with a field or the energy loss as it moves against it. (note that it is also used to define the electron-volt, a unit of energy equal to that gained by an electron as it falls through a pd of 1 v, i.e. w = 1 ev = 1.6 10-19 c 1 v = 1.6 10-19j).in fact this expression is really nothing more than the statement that potential is the potential energy per unit charge. in this case, v= w/qis simply stating that the change in potential energy(or work done) per unit charge is equal to the change in potential (or potential difference), v.student questions: uniform electric fields2electron beamcathode+5 kvanode0 v