Naomi's school supply list includes the following items: one 24-pack crayons
one 12-count colored pencils
ten #2 pencils (not mechanical)
three 1" 3-ring binders
three composition books
one 5" scissors
one three-pack glue sticks
one backpack
Note: Naomi decides to purchase a blue messenger bag instead of a backpack.
Demetrius's school supply list includes the following items:

five 1" 3-ring binders
two packs of paper
three 5-tab dividers
five plastic twin pocket folders
ten #2 pencils (not mechanical)
one ten-pack blue or black pens
one four-pack highlighters
one protractor and compass kit
one calculator
The two siblings pay separtely for their school supplies separately. If Naomi gives the cashier $20, what is the amount of change she will receive? first awnser get brainliest if their correct

1. Naomi spends more

2. Naomi spends $0.59 more

3. total cost is $27.98

4. with 20 dollars Naomi gets $5.72 change back

5. with 15 dollars Demetrius will get $1.30 change back

Step-by-step explanation:

Naomi's total cost:$14.28

0.39+0.79+0.59+(0.79x3)+(0.79x3)+0.39+0.39+6.99=14.28

Demetrius' total cost:$13.70

(0.79x5)+0.79+0.79+(0.59x3)+(0.59x5)+0.59+0.89+0.59+0.59+0.79=13.7

38.5

step-by-step explanation:

lets say, first number = r

second number = 3r+7

total = 49

(r)+(3r+7)= 49

4r+7 = 49

4r = 42

r = 42/4

r= 10.5

3r+7 = 3(10.5)+7 = 38.5

hope this

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}