You have been provided with the following logic expression:
(X+Y) (X+Y')= X

Prove the logic expression in the above scenario
using a Truth table. Show all steps.

If X and Y are Boolean variables, then X + Y represents disjunction (OR) and XY represents conjunction (AND), and X' denotes the negation (NOT). So X + Y = 1 if either X = 1 or Y = 1, and XY = 1 only if both X = 1 or Y = 1.

Now,

(X + Y) (X + Y') = XX + YX + XY' + YY'

… = X + X (Y + Y') + 0

… = X + X

… = X

or in table form,

(- 1, 0 )

step-by-step explanation:

an x- intercept is where the function crosses the x- axis.

to find the x- intercept/s look for the value of x when f(x) = 0

from the given table there are 3 values of x where f(x) = 0

when x = - 1, x = 2, x = 3

the one that is listed is (- 1, 0 )

a

step-by-step explanation: