Use implicit differentiation to solve that the derivative

Given

e ˣʸ = sec(x ²)

take the derivative of both sides:

d/dx [e ˣʸ] = d/dx [sec(x ²)]

Use the chain rule:

e ˣʸ d/dx [xy] = sec(x ²) tan(x ²) d/dx [x ²]

Use the product rule on the left, and the power rule on the right:

e ˣʸ (x dy/dx + y) = sec(x ²) tan(x ²) (2x)

Solve for dy/dx :

e ˣʸ (x dy/dx + y) = 2x sec(x ²) tan(x ²)

x dy/dx + y = 2x e ⁻ˣʸ sec(x ²) tan(x ²)

x dy/dx = 2x e ⁻ˣʸ sec(x ²) tan(x ²) - y

dy/dx = 2e ⁻ˣʸ sec(x ²) tan(x ²) - y/x

Since e ˣʸ = sec(x ²), we simplify further to get

dy/dx = 2 tan(x ²) - y/x

f is the midpoint of