Hello, please help ASAP. Thank you!

23) No

24) No

25) Yes

Step-by-step explanation:

Question 23)

We want to determine if a zero exists between 1 and 2 for the function:

Find the zeros of the function. We can factor:

Zero Product Property:

Solve for each case. Hence:

Therefore, our zeros are at x = 5 and x = -1.

In conclusion, a zero does not exist between 1 and 2.

Question 24)

We have the function:

And we want to determine if a zero exists between 1 and 2.

Factor. We want to find two numbers that multiply to (2)(3) = 6 and that add to -7.

-6 and -1 suffice. Hence:

By the Zero Product Property:

Solve for each case:

Therefore, our zeros are at x = 1/2 and x = 3.

In conclusion, a zero does not exist between 1 and 2.

Question 25)

We have the function:

And we want to determine if a zero exists between -2 and 3.

Factor. Again, we want to find two numbers that multiply to 3(-5) = -15 and that add to -2.

-5 and 3 works perfectly. Hence:

By the Zero Product Property:

Solve for each case:

In conclusion, there indeed exists a zero between -2 and 3.

if the pizza is divided equally into 2 equal halves then you would get

πr^2/2

where r is the radius of the pizza.

happy to

pls mark as brainliest

i believe that the answer is

b. y-1=-2(x-4)

hope this !